Cost Functions

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Cost Functions #

Applied EconomicsDifficulty: ★★★☆☆Depth: 7Unlocks: 6

Fixed, variable, and marginal cost. Average cost curves, economies of scale. Short-run vs long-run cost structures.

Prerequisites (2) #

Derivatives6 atomsOptimization Introduction5 atoms

Unlocks (1) #

Profit Maximizationlvl 4

Referenced by (30) #

Where this concept shows up in the operating-finance and personal-finance graphs.

From Business (30) #

[Supply-SideBusiness

Supply-side analysis is grounded in production cost structures - fixed vs variable costs, marginal cost curves, and economies of scale determine what a firm can profitably produce](/business/supply-side/)[Cost Per UnitBusiness

Average cost curves ARE cost per unit formalized mathematically. The pipeline achieving an order-of-magnitude reduction is movement along the average cost curve driven by economies of scale - exactly what short-run vs long-run cost structure analysis describes.](/business/cost-per-unit/)[income and expensesBusiness

Fixed vs variable cost framework is the mathematical formalization of the same concept used in personal income-and-expenses - marginal cost curves and short-run vs long-run cost structures generalize the personal finance intuition of fixed obligations vs variable spending](/business/income-and-expenses/)[Base FeeBusiness

Fixed cost ($3) plus variable cost ($2/mile) is the textbook cost function decomposition; marginal cost here is constant at $2](/business/base-fee/)[selling costsBusiness

Selling costs decompose into fixed (legal, title), variable (commission as percentage of price), and time-dependent (carrying costs, mortgage payments while listed) components - understanding this cost structure clarifies why the 5-30% range is so wide](/business/selling-costs/)[Cost CenterBusiness

Fixed, variable, and marginal cost curves are the mathematical foundation for cost center analysis - understanding how costs behave with scale, short-run vs long-run cost structures, and economies of scale directly underpins cost center budgeting and performance evaluation](/business/cost-center/)[Unit EconomicsBusiness

Cost functions formalize unit economics mathematically - fixed vs variable cost, marginal cost curves, and economies of scale are exactly what determine whether the AI volume play works (average cost declining as fixed AI costs spread across more units)](/business/unit-economics/)[material costBusiness

Directly teaches the mathematical structure of costs - fixed vs variable, marginal cost, average cost curves, economies of scale - which is exactly the formal framework for reasoning about material cost in engineering design.](/business/material-cost/)[Fixed vs Variable CostsBusiness

Formal microeconomic treatment of the same fixed/variable/marginal cost structure, with average cost curves and economies of scale extending the personal finance intuition to firm-level analysis](/business/fixed-vs-variable-costs/)[Fixed ObligationsBusiness

Fixed vs variable cost is the formal economic framework for this same categorization - personal fixed obligations (rent, insurance) map directly to fixed costs in cost function analysis](/business/fixed-obligations/)[AppreciationBusiness

Depreciation is a cost concept; understanding fixed vs variable cost structures and economies of scale is the formal framing a CFO uses for factories that this concept extends to knowledge work.](/business/appreciation/)[Capital AssetBusiness

Fixed vs variable cost structure is the mathematical foundation for why capitalizing intellectual labor matters - high upfront fixed cost, near-zero marginal cost, and economies of scale are what make the OPEX-to-CAPEX transition valuable](/business/capital-asset/)[P&LBusiness

Formalizes how P&L cost lines behave mathematically - fixed vs variable vs marginal cost, average cost curves, economies of scale - the microeconomic foundation for understanding any cost node on a P&L](/business/p-l/)[Profit & Loss StatementBusiness

Fixed vs variable cost, marginal cost curves, and short-run vs long-run cost structures are the microeconomic foundations for reading the expense side of a P&L (COGS, operating expenses, contribution margin)](/business/profit-loss-statement/)[Cost StructureBusiness

Mathematical formalization of cost structure: fixed, variable, marginal cost curves, economies of scale, short-run vs long-run. The quantitative framework for reasoning about when investing in conditions (shifting the cost curve) dominates direct optimization.](/business/cost-structure/)[Construction SpreadBusiness

Construction spread is a cost differential - your marginal cost of building is lower because you've already made the fixed investment in skill acquisition. Understanding fixed vs variable cost, economies of scale, and short-run vs long-run cost structures explains WHY the spread exists and how it changes as you specialize.](/business/construction-spread/)[P&L ownershipBusiness

Fixed vs variable vs marginal cost, average cost curves, and economies of scale are the mathematical vocabulary for turnaround work - diagnosing whether a struggling brand has a revenue problem or a cost structure problem, and how multi-brand portfolios share fixed costs.](/business/p-l-ownership/)[capacityBusiness

Capacity with C(q)=kq² and q≥1 is a concrete cost function exhibiting increasing marginal cost (MC=2kq) and diseconomies of scale - the exact structures taught in the cost functions node (fixed vs variable cost, average cost curves, short-run constraints).](/business/capacity/)[Cost ReductionBusiness

Provides the mathematical framework - marginal cost, average cost curves, economies of scale - for understanding how architectural changes produce nonlinear (10x) cost reductions as volume scales](/business/cost-reduction/)[cost minimizationBusiness

Direct mathematical foundation - fixed, variable, marginal cost curves and economies of scale are the formal structures that cost minimization operates on](/business/cost-minimization/)[break-evenBusiness

Break-even is where Revenue = Fixed + Variable*Q; understanding fixed vs variable cost structure and average cost curves is the mathematical foundation for computing and interpreting break-even points.](/business/break-even/)[Financial Statement Line ItemBusiness

Fixed, variable, and marginal cost curves directly underpin income statement line items like COGS, SGA, and depreciation, and explain why the income statement decomposes costs the way it does](/business/financial-statement-line-item/)[Financial RatiosBusiness

Fixed vs variable cost structure, marginal cost curves, and economies of scale are the economic foundations that financial ratios like gross margin, operating leverage, and contribution margin actually measure and decompose](/business/financial-ratios/)[CFOBusiness

Fixed vs variable cost, marginal cost curves, and economies of scale ARE the CFO's analytical toolkit formalized. Production cost structure is literally this concept.](/business/cfo/)[SaaSBusiness

Fixed vs variable cost structure and economies of scale are the mathematical framework explaining why SaaS works - vendor spreads fixed development cost across many subscribers, converting your fixed hire/build cost into variable per-seat OpEx](/business/saas/)[Build, Buy, or HireBusiness

Fixed, variable, and marginal cost structures are exactly what you model when comparing build (high fixed, low marginal) vs hire (low fixed, high variable) vs buy (upfront plus maintenance). The math of cost curves drives the decision.](/business/build-buy-or-hire/)[Knowledge WorkBusiness

The literal 'math your CFO uses for factories' - fixed vs variable cost, marginal cost curves, economies of scale - which this concept reapplies to knowledge work with the appreciation twist](/business/knowledge-work/)[Physical CapitalBusiness

Fixed vs variable cost decomposition, economies of scale, and short-run vs long-run cost structures are the microeconomic foundation underlying all physical capital analysis (CapEx amortization, utilization rates, marginal cost of capacity)](/business/physical-capital/)[production linesBusiness

Fixed costs (facility, equipment depreciation), variable costs (materials, labor per unit), marginal cost, and economies of scale are the direct mathematical formalization of production line economics.](/business/production-lines/)[Operating ValueBusiness

Fixed vs variable cost structure, marginal cost curves, and economies of scale determine operating leverage - the mathematical foundation for assessing whether operations create or destroy value at a given scale](/business/operating-value/)

Advanced Learning Details

Graph Position #

55

Depth Cost

6

Fan-Out (ROI)

3

Bottleneck Score

7

Chain Length

Understanding cost functions tells you when a firm should expand, contract, or build a new plant — and why prices sometimes fall when firms get bigger.

TL;DR:

Cost functions describe how total, fixed, variable, average, and marginal costs depend on output; they let you use calculus (Derivatives) and optimization to find profit-maximizing or cost-minimizing output and evaluate economies of scale.

What Is Cost Functions? #

Cost functions are mathematical descriptions of how a firm's costs depend on the quantity of output it produces. At its most basic, a cost function answers: if the firm produces qqq units, what is the total cost TC(q)TC(q)TC(q)? Splitting total cost into components yields intuition and decision rules that managers and economists use.

Key pieces and why they matter

TC(q)=100+5q+0.5q2.TC(q)=100+5q+0.5q^2.TC(q)=100+5q+0.5q2.

Numerically, TC(0)=100TC(0)=100TC(0)=100 (the firm has a $100 fixed cost if it shuts down output), and TC(10)=100+5(10)+0.5(10)2=100+50+50=200TC(10)=100+5(10)+0.5(10)^2=100+50+50=200TC(10)=100+5(10)+0.5(10)2=100+50+50=200.

VC(q)=5q+0.5q2.VC(q)=5q+0.5q^2.VC(q)=5q+0.5q2.

For q=10q=10q=10, VC(10)=5(10)+0.5(100)=50+50=100VC(10)=5(10)+0.5(100)=50+50=100VC(10)=5(10)+0.5(100)=50+50=100.

AC(q)=100+5q+0.5q2q=100q+5+0.5q.AC(q)=\frac{100+5q+0.5q^2}{q}=\frac{100}{q}+5+0.5q.AC(q)=q100+5q+0.5q2​=q100​+5+0.5q.

If q=10q=10q=10, AC(10)=10010+5+0.5(10)=10+5+5=20AC(10)=\frac{100}{10}+5+0.5(10)=10+5+5=20AC(10)=10100​+5+0.5(10)=10+5+5=20.

Notice AC(q)=AFC(q)+AVC(q)AC(q)=AFC(q)+AVC(q)AC(q)=AFC(q)+AVC(q) numerically: $20=10+10$.

MC(q)=TC′(q).MC(q)=TC'(q).MC(q)=TC′(q).

For our example,

MC(q)=ddq(100+5q+0.5q2)=5+q.MC(q)=\frac{d}{dq}\left(100+5q+0.5q^2\right)=5+q.MC(q)=dqd​(100+5q+0.5q2)=5+q.

Numerically, MC(10)=5+10=15MC(10)=5+10=15MC(10)=5+10=15. Marginal cost approximates the cost of the 11th unit; using discrete difference, TC(11)−TC(10)=(100+5(11)+0.5(11)2)−200=100+55+60.5−200=15.5TC(11)-TC(10)=\big(100+5(11)+0.5(11)^2\big)-200=100+55+60.5-200=15.5TC(11)−TC(10)=(100+5(11)+0.5(11)2)−200=100+55+60.5−200=15.5, close to MC(10)=15MC(10)=15MC(10)=15 since the function is smooth.

Short-run vs Long-run

Economies of scale

Why this matters: Marginal cost interacts with price and marginal revenue to determine optimal output (see Optimization Introduction (d3)). Average cost tells you whether a firm covers its costs at a given price and whether expanding output reduces unit costs.

Marginal cost (MC) is central because in competitive markets the profit-maximizing condition often equates price to marginal cost (when firms are price takers). Average costs determine profitability and long-run entry/exit.

Formal relationships and calculus intuition (reference: Derivatives (d2))

MC(q)=TC′(q).MC(q)=TC'(q).MC(q)=TC′(q).

Example: If TC(q)=50+2q+0.1q2TC(q)=50+2q+0.1q^2TC(q)=50+2q+0.1q2, then

MC(q)=2+0.2q.MC(q)=2+0.2q.MC(q)=2+0.2q.

Numerically, MC(20)=2+0.2(20)=2+4=6MC(20)=2+0.2(20)=2+4=6MC(20)=2+0.2(20)=2+4=6. So the additional cost at output 20 is $6 per extra unit.

AC′(q)=q⋅TC′(q)−TC(q)q2=q⋅MC(q)−TC(q)q2.AC'(q)=\frac{q\cdot TC'(q)-TC(q)}{q^2}=\frac{q\cdot MC(q)-TC(q)}{q^2}.AC′(q)=q2q⋅TC′(q)−TC(q)​=q2q⋅MC(q)−TC(q)​.

Setting AC′(q)=0AC'(q)=0AC′(q)=0 gives q⋅MC(q)−TC(q)=0⇒MC(q)=TC(q)/q=AC(q)q\cdot MC(q)-TC(q)=0\Rightarrow MC(q)=TC(q)/q=AC(q)q⋅MC(q)−TC(q)=0⇒MC(q)=TC(q)/q=AC(q). Thus the stationary point of ACACAC occurs where MC=ACMC=ACMC=AC. If that point is a minimum, MC crosses AC from below.

Concrete numeric check: Take TC(q)=100+5q+0.5q2TC(q)=100+5q+0.5q^2TC(q)=100+5q+0.5q2 as before. Then AC(q)=100/q+5+0.5qAC(q)=100/q+5+0.5qAC(q)=100/q+5+0.5q and MC(q)=5+qMC(q)=5+qMC(q)=5+q. Solve MC(q)=AC(q)MC(q)=AC(q)MC(q)=AC(q):

5+q=100q+5+0.5q⇒q=100q+0.5q⇒q−0.5q=100q⇒0.5q=100q⇒q2=200⇒q=200≈14.142.5+q=\frac{100}{q}+5+0.5q\Rightarrow q=\frac{100}{q}+0.5q\Rightarrow q-0.5q=\frac{100}{q}\Rightarrow 0.5q=\frac{100}{q}\Rightarrow q^2=200\Rightarrow q=\sqrt{200}\approx14.142.5+q=q100​+5+0.5q⇒q=q100​+0.5q⇒q−0.5q=q100​⇒0.5q=q100​⇒q2=200⇒q=200​≈14.142.

Numerically check: MC(14.142)≈5+14.142=19.142MC(14.142)\approx5+14.142=19.142MC(14.142)≈5+14.142=19.142. And AC(14.142)=100/14.142+5+0.5(14.142)≈7.071+5+7.071=19.142AC(14.142)=100/14.142+5+0.5(14.142)\approx7.071+5+7.071=19.142AC(14.142)=100/14.142+5+0.5(14.142)≈7.071+5+7.071=19.142, matching.

Local decision rules and short-run shutdown condition (link to Optimization Introduction (d3))

Example numeric decision: If price p=19p=19p=19 and MC(q)=5+qMC(q)=5+qMC(q)=5+q, then optimal output solves $5+q=19\Rightarrow q=14.Thismatchestheearlier. This matches the earlier .ThismatchestheearlierAC$ minimum example and shows how calculus directly produces the optimal output.

Concrete numbers: For VC(q)=5q+0.5q2VC(q)=5q+0.5q^2VC(q)=5q+0.5q2, AVC(q)=5+0.5qAVC(q)=5+0.5qAVC(q)=5+0.5q has minimum at q=0q=0q=0 (since it's increasing here) with AVC(0)=5AVC(0)=5AVC(0)=5. If market price p=4p=4p=4, since p<5p<5p<5 the firm should shut down. If p=10p=10p=10, solve MC=5+q=10⇒q=5MC=5+q=10\Rightarrow q=5MC=5+q=10⇒q=5.

This section shows how derivatives (Derivatives (d2)) and optimization first-order conditions (Optimization Introduction (d3)) translate to managerial rules: set output where p=MCp=MCp=MC, check AVCAVCAVC to decide shutdown, and use ACACAC to check profitability.

Core Mechanic 2: Short-Run vs Long-Run Costs and Economies of Scale #

Understanding the distinction between short-run and long-run cost structures is essential for planning capacity and for understanding industry dynamics (entry, exit, and firm size).

Short-run cost structure

Example: Suppose a firm has a factory requiring FC=200FC=200FC=200 and variable cost VCSR(q)=10q+0.2q2VC_{SR}(q)=10q+0.2q^2VCSR​(q)=10q+0.2q2. Then

TCSR(q)=200+10q+0.2q2,TC_{SR}(q)=200+10q+0.2q^2,TCSR​(q)=200+10q+0.2q2,

MCSR(q)=10+0.4q,MC_{SR}(q)=10+0.4q,MCSR​(q)=10+0.4q,

ACSR(q)=200q+10+0.2q.AC_{SR}(q)=\frac{200}{q}+10+0.2q.ACSR​(q)=q200​+10+0.2q.

Numerical check: at q=20q=20q=20, TCSR(20)=200+200+80=480TC_{SR}(20)=200+200+80=480TCSR​(20)=200+200+80=480 (wait: compute carefully: $1020=200$, $0.2400=80,so, so ,soTC_{SR}=480),), ),MC_{SR}(20)=10+0.4(20)=18$, $AC_{SR}(20)=200/20+10+0.2(20)=10+10+4=24$.

Long-run cost structure and the envelope theorem

Algebraically, suppose plant size is parameterized by kkk (e.g., capacity). For each kkk we have TC(q;k)=FC(k)+VC(q;k)TC(q;k)=FC(k)+VC(q;k)TC(q;k)=FC(k)+VC(q;k). Then

LTC(q)=min⁡kTC(q;k).LTC(q)=\min_k TC(q;k).LTC(q)=kmin​TC(q;k).

Example (simplified): Suppose there are two discrete plant sizes:

For q=10q=10q=10, TCS(10)=100+60+20=180TC_S(10)=100+60+20=180TCS​(10)=100+60+20=180, TCL(10)=400+30+10=440TC_L(10)=400+30+10=440TCL​(10)=400+30+10=440. So the small plant is cheaper at low output. For q=200q=200q=200, TCS(200)=100+1200+8000=9320TC_S(200)=100+1200+8000=9320TCS​(200)=100+1200+8000=9320, TCL(200)=400+600+4000=5000TC_L(200)=400+600+4000=5000TCL​(200)=400+600+4000=5000; the large plant is cheaper at high output. The long-run cost at each qqq picks the cheaper plant, creating an LAC(q)LAC(q)LAC(q) that can fall then rise depending on technology.

Economies of scale (technical/market meanings)

Concrete numeric instance: Take LTC(q)=10q0.8LTC(q)=10q^{0.8}LTC(q)=10q0.8. Then LAC(q)=10q−0.2LAC(q)=10q^{-0.2}LAC(q)=10q−0.2. For q=100q=100q=100, LAC(100)=10(100)−0.2=10/(1000.2)=10/(≈2.5119)≈3.98LAC(100)=10(100)^{-0.2}=10/(100^{0.2})=10/(\approx2.5119)\approx3.98LAC(100)=10(100)−0.2=10/(1000.2)=10/(≈2.5119)≈3.98. For q=1000q=1000q=1000, LAC(1000)=10(1000)−0.2=10/(10000.2)=10/(≈3.981)≈2.51LAC(1000)=10(1000)^{-0.2}=10/(1000^{0.2})=10/(\approx3.981)\approx2.51LAC(1000)=10(1000)−0.2=10/(10000.2)=10/(≈3.981)≈2.51. So average cost falls with scale: economies of scale.

Returns to scale vs economies of scale distinction

Long-run planning decisions

Applications and Connections #

Cost functions are used across microeconomics, managerial economics, and public policy. Here are concrete applications and how this connects to downstream topics.

Pricing and output decisions in market structures

Cost-benefit, entry/exit, and long-run industry supply

Cost estimation and managerial accounting

Network industries and scale economies

Connection to welfare analysis

Downstream topics that use cost function mechanics

Concrete managerial checklist

Every formula in this lesson ties back to calculus (Derivatives (d2)) for rates of change and to optimization first-order conditions (Optimization Introduction (d3)) for choosing qqq to maximize profit or minimize cost. These tools give actionable rules for pricing, capacity choice, and policy design.

Worked Examples (3) #

Basic MC and AC computation #

Given TC(q)=120+4q+0.25q2TC(q)=120+4q+0.25q^2TC(q)=120+4q+0.25q2, compute FCFCFC, VC(q)VC(q)VC(q), MC(q)MC(q)MC(q), AC(q)AC(q)AC(q), and evaluate them at q=40q=40q=40.

  1. Identify fixed cost (constant term): FC=120FC=120FC=120.
  2. Compute variable cost: VC(q)=TC(q)−FC=4q+0.25q2VC(q)=TC(q)-FC=4q+0.25q^2VC(q)=TC(q)−FC=4q+0.25q2. For q=40q=40q=40, VC(40)=4(40)+0.25(1600)=160+400=560VC(40)=4(40)+0.25(1600)=160+400=560VC(40)=4(40)+0.25(1600)=160+400=560.
  3. Differentiate to get marginal cost: MC(q)=TC′(q)=4+0.5qMC(q)=TC'(q)=4+0.5qMC(q)=TC′(q)=4+0.5q. For q=40q=40q=40, MC(40)=4+0.5(40)=4+20=24MC(40)=4+0.5(40)=4+20=24MC(40)=4+0.5(40)=4+20=24.
  4. Compute average total cost: AC(q)=TC(q)/q=120+4q+0.25q2q=120q+4+0.25qAC(q)=TC(q)/q=\frac{120+4q+0.25q^2}{q}=\frac{120}{q}+4+0.25qAC(q)=TC(q)/q=q120+4q+0.25q2​=q120​+4+0.25q. For q=40q=40q=40, AC(40)=120/40+4+0.25(40)=3+4+10=17AC(40)=120/40+4+0.25(40)=3+4+10=17AC(40)=120/40+4+0.25(40)=3+4+10=17.
  5. Verify AC=AVC+AFCAC=AVC+AFCAC=AVC+AFC: AFC(40)=120/40=3AFC(40)=120/40=3AFC(40)=120/40=3, AVC(40)=VC(40)/40=560/40=14AVC(40)=VC(40)/40=560/40=14AVC(40)=VC(40)/40=560/40=14, sum $3+14=17,matching, matching ,matchingAC(40)$.

Insight: This example reinforces that MCMCMC is the derivative of TCTCTC, FCFCFC is the constant term, and averages decompose cleanly; numerically checking identities is a useful verification step.

Shutdown decision using AVC minimum #

A firm has TC(q)=200+8q+0.5q2TC(q)=200+8q+0.5q^2TC(q)=200+8q+0.5q2. Market price is p=9p=9p=9. Should the firm produce in the short run? If yes, find optimal qqq; if no, explain why.

  1. Compute VC(q)=8q+0.5q2VC(q)=8q+0.5q^2VC(q)=8q+0.5q2 and AVC(q)=VC(q)q=8+0.5qAVC(q)=\frac{VC(q)}{q}=8+0.5qAVC(q)=qVC(q)​=8+0.5q.
  2. Find minimum of AVC(q)AVC(q)AVC(q): AVC is linear increasing in qqq here with slope $0.5,sotheminimumoccursat, so the minimum occurs at ,sotheminimumoccursatq=0with with withAVC(0)=8$. (Interpretation: marginally, AVC increases from 8.)
  3. Compare market price p=9p=9p=9 to min⁡AVC=8\min AVC=8minAVC=8. Since p>8p>8p>8, the firm should produce (not shut down) because price covers variable cost at some positive output.
  4. Compute marginal cost: MC(q)=TC′(q)=8+qMC(q)=TC'(q)=8+qMC(q)=TC′(q)=8+q. Set p=MCp=MCp=MC to find interior optimum: $9=8+q\Rightarrow q=1$.
  5. Compute profit (optional check): TR=9(1)=9TR=9(1)=9TR=9(1)=9, TC(1)=200+8+0.5=208.5TC(1)=200+8+0.5=208.5TC(1)=200+8+0.5=208.5, profit =9−208.5=−199.5=9-208.5=-199.5=9−208.5=−199.5. Loss is large, but since loss (−199.5)(-199.5)(−199.5) is less than fixed cost loss of −200-200−200 from shutting down, producing minimizes loss in the short run.

Insight: Even when producing yields an economic loss, producing can be better than shutting down if price covers variable costs; calculus provides the production rule p=MCp=MCp=MC for interior solutions.

Long-run plant choice and economies of scale #

Two plant options: Small plant TCS(q)=150+6q+0.4q2TC_S(q)=150+6q+0.4q^2TCS​(q)=150+6q+0.4q2, Large plant TCL(q)=500+3q+0.2q2TC_L(q)=500+3q+0.2q^2TCL​(q)=500+3q+0.2q2. For q=50q=50q=50 determine which plant minimizes cost. Then compute LAC(50)LAC(50)LAC(50) and comment on economies of scale comparing q=50q=50q=50 to q=200q=200q=200.

  1. Compute TCS(50)=150+6(50)+0.4(2500)=150+300+1000=1450TC_S(50)=150+6(50)+0.4(2500)=150+300+1000=1450TCS​(50)=150+6(50)+0.4(2500)=150+300+1000=1450.
  2. Compute TCL(50)=500+3(50)+0.2(2500)=500+150+500=1150TC_L(50)=500+3(50)+0.2(2500)=500+150+500=1150TCL​(50)=500+3(50)+0.2(2500)=500+150+500=1150.
  3. Compare costs: TCL(50)=1150<TCS(50)=1450TC_L(50)=1150<TC_S(50)=1450TCL​(50)=1150<TCS​(50)=1450, so the large plant is cheaper for q=50q=50q=50.
  4. Compute long-run average cost at q=50q=50q=50: LAC(50)=TCL(50)/50=1150/50=23LAC(50)=TC_L(50)/50=1150/50=23LAC(50)=TCL​(50)/50=1150/50=23 (since large plant chosen).
  5. Now evaluate at q=200q=200q=200: TCS(200)=150+1200+0.4(40000)=150+1200+16000=17350TC_S(200)=150+1200+0.4(40000)=150+1200+16000=17350TCS​(200)=150+1200+0.4(40000)=150+1200+16000=17350. TCL(200)=500+600+0.2(40000)=500+600+8000=9100TC_L(200)=500+600+0.2(40000)=500+600+8000=9100TCL​(200)=500+600+0.2(40000)=500+600+8000=9100. Then LAC(200)=9100/200=45.5.CompareLAC(200)=9100/200=45.5. Compare LAC(200)=9100/200=45.5.CompareLAC(50)=23to to toLAC(200)=45.5$: average cost increased going from 50 to 200, indicating diseconomies of scale in this numeric example across that range. (Interpret: the large plant is better at low to medium q here but both plants generate higher average cost at much larger q due to quadratic variation.)

Insight: Picking among plant options is an optimization over discrete or continuous capital choices; the long-run average cost is the lower envelope of short-run costs and can exhibit economies or diseconomies of scale depending on technology parameters.

Key Takeaways #

Common Mistakes #

Practice #

easy

Easy: Given TC(q)=80+3q+0.1q2TC(q)=80+3q+0.1q^2TC(q)=80+3q+0.1q2, compute MC(q)MC(q)MC(q) and AC(q)AC(q)AC(q), then evaluate MC(20)MC(20)MC(20) and AC(20)AC(20)AC(20).

Hint: Differentiate TCTCTC for MCMCMC. For ACACAC, divide TCTCTC by qqq and plug in q=20q=20q=20.

Show solution

MC(q)=3+0.2q, so MC(20)=3+0.2(20)=7. AC(q)=80/q+3+0.1q, so AC(20)=80/20+3+0.1(20)=4+3+2=9.

medium

Medium: A firm has short-run cost TCSR(q)=250+10q+0.5q2TC_{SR}(q)=250+10q+0.5q^2TCSR​(q)=250+10q+0.5q2. Market price is p=35p=35p=35. Should the firm produce in the short run? If yes, find the profit-maximizing qqq and the resulting profit.

Hint: Compute AVCAVCAVC and its minimum to check shutdown; then set p=MCp=MCp=MC for the interior solution (Optimization Introduction (d3)).

Show solution

VC(q)=10q+0.5q^2 so AVC(q)=10+0.5q, minimum at q=0 with AVC_min=10. Since p=35>10, produce. MC(q)=10+q. Set p=MC: 35=10+q => q=25. Compute TR=3525=875. TC=250+1025+0.5*625=250+250+312.5=812.5. Profit=875-812.5=62.5.

hard

Hard: You are choosing plant size k≥0 affecting fixed and variable costs: FC(k)=100kFC(k)=100kFC(k)=100k, VC(q;k)=5q+0.2k−1q2VC(q;k)=5q+0.2k^{-1}q^2VC(q;k)=5q+0.2k−1q2. For a required output q0=100, choose k to minimize TC(q0;k)=100k+5(100)+0.2k−1(100)2TC(q_0;k)=100k+5(100)+0.2k^{-1}(100)^2TC(q0​;k)=100k+5(100)+0.2k−1(100)2. Find optimal k and the minimized total and average cost. (Edge case reasoning: ensure k>0.)

Hint: Treat TC as a function of k and differentiate w.r.t k; use first-order condition and check second derivative for minimization. This uses Optimization Introduction (d3).

Show solution

Write TC(k)=100k+500+0.2(10000)/k=100k+500+2000/k. Differentiate: TC'(k)=100-2000/k^2. Set =0 => 100=2000/k^2 => k^2=2000/100=20 => k=\sqrt{20}\approx4.4721 (positive root). Second derivative TC''(k)=4000/k^3>0 so minimizer. Minimized TC=100(4.4721)+500+2000/4.4721 ≈447.21+500+447.21=1394.42. Average cost =TC/100 ≈13.9442.

Connections #

Looking back: In Derivatives (d2) we learned that derivatives give instantaneous rates of change; here MC(q)=TC′(q)MC(q)=TC'(q)MC(q)=TC′(q) is a direct application of that concept to economics. In Optimization Introduction (d3) we learned how to set first-order conditions to find maxima/minima under constraints; here we set p=MCp=MCp=MC (or MR=MCMR=MCMR=MC) and differentiate cost with respect to plant size to find long-run minimizers. Looking forward: mastering cost functions enables analysis of production functions and duality (cost minimization), long-run competitive equilibria (entry/exit and zero-profit conditions), industrial organization topics like natural monopoly and oligopoly pricing strategies, and empirical estimation of cost and production technologies. Specific downstream concepts that require this material include: derivation of supply curves from cost functions, welfare analysis comparing price and marginal cost, and investment/capital choice models in dynamic firm theory.

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